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¿Cómo vas a descomponer esta log(14*log(2)+2*4^x*log(2))/(2*log(2)) expresión en fracciones?

Expresión a simplificar:

Solución

Ha introducido [src]
   /               x       \
log\14*log(2) + 2*4 *log(2)/
----------------------------
          2*log(2)          
$$\frac{\log{\left(2 \cdot 4^{x} \log{\left(2 \right)} + 14 \log{\left(2 \right)} \right)}}{2 \log{\left(2 \right)}}$$
log(14*log(2) + (2*4^x)*log(2))/((2*log(2)))
Simplificación general [src]
   //     x\       \
log\\7 + 4 /*log(4)/
--------------------
      2*log(2)      
$$\frac{\log{\left(\left(4^{x} + 7\right) \log{\left(4 \right)} \right)}}{2 \log{\left(2 \right)}}$$
log((7 + 4^x)*log(4))/(2*log(2))
Respuesta numérica [src]
0.721347520444482*log(14*log(2) + (2*4^x)*log(2))
0.721347520444482*log(14*log(2) + (2*4^x)*log(2))
Denominador común [src]
       /     x\              
1   log\7 + 4 / + log(log(2))
- + -------------------------
2            2*log(2)        
$$\frac{\log{\left(4^{x} + 7 \right)} + \log{\left(\log{\left(2 \right)} \right)}}{2 \log{\left(2 \right)}} + \frac{1}{2}$$
1/2 + (log(7 + 4^x) + log(log(2)))/(2*log(2))
Unión de expresiones racionales [src]
   /  /     x\       \
log\2*\7 + 4 /*log(2)/
----------------------
       2*log(2)       
$$\frac{\log{\left(2 \left(4^{x} + 7\right) \log{\left(2 \right)} \right)}}{2 \log{\left(2 \right)}}$$
log(2*(7 + 4^x)*log(2))/(2*log(2))
Potencias [src]
   /             1 + 2*x       \
log\14*log(2) + 2       *log(2)/
--------------------------------
            2*log(2)            
$$\frac{\log{\left(2^{2 x + 1} \log{\left(2 \right)} + 14 \log{\left(2 \right)} \right)}}{2 \log{\left(2 \right)}}$$
log(14*log(2) + 2^(1 + 2*x)*log(2))/(2*log(2))