Sr Examen

Ecuación diferencial (y-2)dx-(x-y-1)dy=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
     d                 d          d                  
-2 + --(y(x))*y(x) - x*--(y(x)) + --(y(x)) + y(x) = 0
     dx                dx         dx                 
$$- x \frac{d}{d x} y{\left(x \right)} + y{\left(x \right)} \frac{d}{d x} y{\left(x \right)} + y{\left(x \right)} + \frac{d}{d x} y{\left(x \right)} - 2 = 0$$
-x*y' + y*y' + y + y' - 2 = 0
Respuesta [src]
                  /         -C1\
            C1 + W\(3 - x)*e   /
y(x) = 2 + e                    
$$y{\left(x \right)} = e^{C_{1} + W\left(\left(3 - x\right) e^{- C_{1}}\right)} + 2$$
Clasificación
factorable
1st exact
linear coefficients
1st power series
lie group
1st exact Integral
linear coefficients Integral