absolute(x+2)=a*(x-3) la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Solución detallada
Para cada expresión dentro del módulo en la ecuación
admitimos los casos cuando la expresión correspondiente es ">= 0" o "< 0",
resolvemos las ecuaciones obtenidas.
1. x + 2 ≥ 0 x + 2 \geq 0 x + 2 ≥ 0 o
− 2 ≤ x ∧ x < ∞ -2 \leq x \wedge x < \infty − 2 ≤ x ∧ x < ∞ obtenemos la ecuación
− a ( x − 3 ) + ( x + 2 ) = 0 - a \left(x - 3\right) + \left(x + 2\right) = 0 − a ( x − 3 ) + ( x + 2 ) = 0 simplificamos, obtenemos
− a ( x − 3 ) + x + 2 = 0 - a \left(x - 3\right) + x + 2 = 0 − a ( x − 3 ) + x + 2 = 0 la resolución en este intervalo:
x 1 = 3 a + 2 a − 1 x_{1} = \frac{3 a + 2}{a - 1} x 1 = a − 1 3 a + 2 2. x + 2 < 0 x + 2 < 0 x + 2 < 0 o
− ∞ < x ∧ x < − 2 -\infty < x \wedge x < -2 − ∞ < x ∧ x < − 2 obtenemos la ecuación
− a ( x − 3 ) + ( − x − 2 ) = 0 - a \left(x - 3\right) + \left(- x - 2\right) = 0 − a ( x − 3 ) + ( − x − 2 ) = 0 simplificamos, obtenemos
− a ( x − 3 ) − x − 2 = 0 - a \left(x - 3\right) - x - 2 = 0 − a ( x − 3 ) − x − 2 = 0 la resolución en este intervalo:
x 2 = 3 a − 2 a + 1 x_{2} = \frac{3 a - 2}{a + 1} x 2 = a + 1 3 a − 2 Entonces la respuesta definitiva es:
x 1 = 3 a + 2 a − 1 x_{1} = \frac{3 a + 2}{a - 1} x 1 = a − 1 3 a + 2 x 2 = 3 a − 2 a + 1 x_{2} = \frac{3 a - 2}{a + 1} x 2 = a + 1 3 a − 2
Suma y producto de raíces
[src]
//2 + 3*a 5*a \ //2 + 3*a 5*a \ //-2 + 3*a 5*a \ //-2 + 3*a 5*a \
||------- for ------ >= 0| ||------- for ------ >= 0| ||-------- for ----- < 0| ||-------- for ----- < 0|
I*im|< -1 + a -1 + a | + re|< -1 + a -1 + a | + I*im|< 1 + a 1 + a | + re|< 1 + a 1 + a |
|| | || | || | || |
\\ nan otherwise / \\ nan otherwise / \\ nan otherwise / \\ nan otherwise /
( re ( { 3 a + 2 a − 1 for 5 a a − 1 ≥ 0 NaN otherwise ) + i im ( { 3 a + 2 a − 1 for 5 a a − 1 ≥ 0 NaN otherwise ) ) + ( re ( { 3 a − 2 a + 1 for 5 a a + 1 < 0 NaN otherwise ) + i im ( { 3 a − 2 a + 1 for 5 a a + 1 < 0 NaN otherwise ) ) \left(\operatorname{re}{\left(\begin{cases} \frac{3 a + 2}{a - 1} & \text{for}\: \frac{5 a}{a - 1} \geq 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} + i \operatorname{im}{\left(\begin{cases} \frac{3 a + 2}{a - 1} & \text{for}\: \frac{5 a}{a - 1} \geq 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)}\right) + \left(\operatorname{re}{\left(\begin{cases} \frac{3 a - 2}{a + 1} & \text{for}\: \frac{5 a}{a + 1} < 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} + i \operatorname{im}{\left(\begin{cases} \frac{3 a - 2}{a + 1} & \text{for}\: \frac{5 a}{a + 1} < 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)}\right) ( re ( { a − 1 3 a + 2 NaN for a − 1 5 a ≥ 0 otherwise ) + i im ( { a − 1 3 a + 2 NaN for a − 1 5 a ≥ 0 otherwise ) ) + ( re ( { a + 1 3 a − 2 NaN for a + 1 5 a < 0 otherwise ) + i im ( { a + 1 3 a − 2 NaN for a + 1 5 a < 0 otherwise ) )
//-2 + 3*a 5*a \ //2 + 3*a 5*a \ //-2 + 3*a 5*a \ //2 + 3*a 5*a \
||-------- for ----- < 0| ||------- for ------ >= 0| ||-------- for ----- < 0| ||------- for ------ >= 0|
I*im|< 1 + a 1 + a | + I*im|< -1 + a -1 + a | + re|< 1 + a 1 + a | + re|< -1 + a -1 + a |
|| | || | || | || |
\\ nan otherwise / \\ nan otherwise / \\ nan otherwise / \\ nan otherwise /
re ( { 3 a + 2 a − 1 for 5 a a − 1 ≥ 0 NaN otherwise ) + re ( { 3 a − 2 a + 1 for 5 a a + 1 < 0 NaN otherwise ) + i im ( { 3 a + 2 a − 1 for 5 a a − 1 ≥ 0 NaN otherwise ) + i im ( { 3 a − 2 a + 1 for 5 a a + 1 < 0 NaN otherwise ) \operatorname{re}{\left(\begin{cases} \frac{3 a + 2}{a - 1} & \text{for}\: \frac{5 a}{a - 1} \geq 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} + \operatorname{re}{\left(\begin{cases} \frac{3 a - 2}{a + 1} & \text{for}\: \frac{5 a}{a + 1} < 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} + i \operatorname{im}{\left(\begin{cases} \frac{3 a + 2}{a - 1} & \text{for}\: \frac{5 a}{a - 1} \geq 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} + i \operatorname{im}{\left(\begin{cases} \frac{3 a - 2}{a + 1} & \text{for}\: \frac{5 a}{a + 1} < 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} re ( { a − 1 3 a + 2 NaN for a − 1 5 a ≥ 0 otherwise ) + re ( { a + 1 3 a − 2 NaN for a + 1 5 a < 0 otherwise ) + i im ( { a − 1 3 a + 2 NaN for a − 1 5 a ≥ 0 otherwise ) + i im ( { a + 1 3 a − 2 NaN for a + 1 5 a < 0 otherwise )
/ //2 + 3*a 5*a \ //2 + 3*a 5*a \\ / //-2 + 3*a 5*a \ //-2 + 3*a 5*a \\
| ||------- for ------ >= 0| ||------- for ------ >= 0|| | ||-------- for ----- < 0| ||-------- for ----- < 0||
|I*im|< -1 + a -1 + a | + re|< -1 + a -1 + a ||*|I*im|< 1 + a 1 + a | + re|< 1 + a 1 + a ||
| || | || || | || | || ||
\ \\ nan otherwise / \\ nan otherwise // \ \\ nan otherwise / \\ nan otherwise //
( re ( { 3 a + 2 a − 1 for 5 a a − 1 ≥ 0 NaN otherwise ) + i im ( { 3 a + 2 a − 1 for 5 a a − 1 ≥ 0 NaN otherwise ) ) ( re ( { 3 a − 2 a + 1 for 5 a a + 1 < 0 NaN otherwise ) + i im ( { 3 a − 2 a + 1 for 5 a a + 1 < 0 NaN otherwise ) ) \left(\operatorname{re}{\left(\begin{cases} \frac{3 a + 2}{a - 1} & \text{for}\: \frac{5 a}{a - 1} \geq 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} + i \operatorname{im}{\left(\begin{cases} \frac{3 a + 2}{a - 1} & \text{for}\: \frac{5 a}{a - 1} \geq 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)}\right) \left(\operatorname{re}{\left(\begin{cases} \frac{3 a - 2}{a + 1} & \text{for}\: \frac{5 a}{a + 1} < 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} + i \operatorname{im}{\left(\begin{cases} \frac{3 a - 2}{a + 1} & \text{for}\: \frac{5 a}{a + 1} < 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)}\right) ( re ( { a − 1 3 a + 2 NaN for a − 1 5 a ≥ 0 otherwise ) + i im ( { a − 1 3 a + 2 NaN for a − 1 5 a ≥ 0 otherwise ) ) ( re ( { a + 1 3 a − 2 NaN for a + 1 5 a < 0 otherwise ) + i im ( { a + 1 3 a − 2 NaN for a + 1 5 a < 0 otherwise ) )
// 2 \ / 2 \
|\3*im (a) + (1 + re(a))*(-2 + 3*re(a)) + 5*I*im(a)/*\3*im (a) + (-1 + re(a))*(2 + 3*re(a)) - 5*I*im(a)/
|------------------------------------------------------------------------------------------------------- for And(a > -1, a < 0)
< / 2 2 \ / 2 2 \
| \(1 + re(a)) + im (a)/*\(-1 + re(a)) + im (a)/
|
\ nan otherwise
{ ( ( re ( a ) − 1 ) ( 3 re ( a ) + 2 ) + 3 ( im ( a ) ) 2 − 5 i im ( a ) ) ( ( re ( a ) + 1 ) ( 3 re ( a ) − 2 ) + 3 ( im ( a ) ) 2 + 5 i im ( a ) ) ( ( re ( a ) − 1 ) 2 + ( im ( a ) ) 2 ) ( ( re ( a ) + 1 ) 2 + ( im ( a ) ) 2 ) for a > − 1 ∧ a < 0 NaN otherwise \begin{cases} \frac{\left(\left(\operatorname{re}{\left(a\right)} - 1\right) \left(3 \operatorname{re}{\left(a\right)} + 2\right) + 3 \left(\operatorname{im}{\left(a\right)}\right)^{2} - 5 i \operatorname{im}{\left(a\right)}\right) \left(\left(\operatorname{re}{\left(a\right)} + 1\right) \left(3 \operatorname{re}{\left(a\right)} - 2\right) + 3 \left(\operatorname{im}{\left(a\right)}\right)^{2} + 5 i \operatorname{im}{\left(a\right)}\right)}{\left(\left(\operatorname{re}{\left(a\right)} - 1\right)^{2} + \left(\operatorname{im}{\left(a\right)}\right)^{2}\right) \left(\left(\operatorname{re}{\left(a\right)} + 1\right)^{2} + \left(\operatorname{im}{\left(a\right)}\right)^{2}\right)} & \text{for}\: a > -1 \wedge a < 0 \\\text{NaN} & \text{otherwise} \end{cases} ⎩ ⎨ ⎧ ( ( re ( a ) − 1 ) 2 + ( im ( a ) ) 2 ) ( ( re ( a ) + 1 ) 2 + ( im ( a ) ) 2 ) ( ( re ( a ) − 1 ) ( 3 re ( a ) + 2 ) + 3 ( im ( a ) ) 2 − 5 i im ( a ) ) ( ( re ( a ) + 1 ) ( 3 re ( a ) − 2 ) + 3 ( im ( a ) ) 2 + 5 i im ( a ) ) NaN for a > − 1 ∧ a < 0 otherwise
Piecewise(((3*im(a)^2 + (1 + re(a))*(-2 + 3*re(a)) + 5*i*im(a))*(3*im(a)^2 + (-1 + re(a))*(2 + 3*re(a)) - 5*i*im(a))/(((1 + re(a))^2 + im(a)^2)*((-1 + re(a))^2 + im(a)^2)), (a > -1)∧(a < 0)), (nan, True))
//2 + 3*a 5*a \ //2 + 3*a 5*a \
||------- for ------ >= 0| ||------- for ------ >= 0|
x1 = I*im|< -1 + a -1 + a | + re|< -1 + a -1 + a |
|| | || |
\\ nan otherwise / \\ nan otherwise /
x 1 = re ( { 3 a + 2 a − 1 for 5 a a − 1 ≥ 0 NaN otherwise ) + i im ( { 3 a + 2 a − 1 for 5 a a − 1 ≥ 0 NaN otherwise ) x_{1} = \operatorname{re}{\left(\begin{cases} \frac{3 a + 2}{a - 1} & \text{for}\: \frac{5 a}{a - 1} \geq 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} + i \operatorname{im}{\left(\begin{cases} \frac{3 a + 2}{a - 1} & \text{for}\: \frac{5 a}{a - 1} \geq 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} x 1 = re ( { a − 1 3 a + 2 NaN for a − 1 5 a ≥ 0 otherwise ) + i im ( { a − 1 3 a + 2 NaN for a − 1 5 a ≥ 0 otherwise )
//-2 + 3*a 5*a \ //-2 + 3*a 5*a \
||-------- for ----- < 0| ||-------- for ----- < 0|
x2 = I*im|< 1 + a 1 + a | + re|< 1 + a 1 + a |
|| | || |
\\ nan otherwise / \\ nan otherwise /
x 2 = re ( { 3 a − 2 a + 1 for 5 a a + 1 < 0 NaN otherwise ) + i im ( { 3 a − 2 a + 1 for 5 a a + 1 < 0 NaN otherwise ) x_{2} = \operatorname{re}{\left(\begin{cases} \frac{3 a - 2}{a + 1} & \text{for}\: \frac{5 a}{a + 1} < 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} + i \operatorname{im}{\left(\begin{cases} \frac{3 a - 2}{a + 1} & \text{for}\: \frac{5 a}{a + 1} < 0 \\\text{NaN} & \text{otherwise} \end{cases}\right)} x 2 = re ( { a + 1 3 a − 2 NaN for a + 1 5 a < 0 otherwise ) + i im ( { a + 1 3 a − 2 NaN for a + 1 5 a < 0 otherwise )
x2 = re(Piecewise(((3*a - 2)/(a + 1, 5*a/(a + 1) < 0), (nan, True))) + i*im(Piecewise(((3*a - 2)/(a + 1), 5*a/(a + 1) < 0), (nan, True))))