Integral de sin^2x/(1+cosx) dx
Solución
Respuesta (Indefinida)
[src]
/
| /x\ 2/x\
| 2 2*tan|-| x*tan |-|
| sin (x) x \2/ \2/
| ---------- dx = C + ----------- - ----------- + -----------
| 1 + cos(x) 2/x\ 2/x\ 2/x\
| 1 + tan |-| 1 + tan |-| 1 + tan |-|
/ \2/ \2/ \2/
$$\int \frac{\sin^{2}{\left(x \right)}}{\cos{\left(x \right)} + 1}\, dx = C + \frac{x \tan^{2}{\left(\frac{x}{2} \right)}}{\tan^{2}{\left(\frac{x}{2} \right)} + 1} + \frac{x}{\tan^{2}{\left(\frac{x}{2} \right)} + 1} - \frac{2 \tan{\left(\frac{x}{2} \right)}}{\tan^{2}{\left(\frac{x}{2} \right)} + 1}$$
2
1 tan (1/2) 2*tan(1/2)
------------- + ------------- - -------------
2 2 2
1 + tan (1/2) 1 + tan (1/2) 1 + tan (1/2)
$$- \frac{2 \tan{\left(\frac{1}{2} \right)}}{\tan^{2}{\left(\frac{1}{2} \right)} + 1} + \frac{\tan^{2}{\left(\frac{1}{2} \right)}}{\tan^{2}{\left(\frac{1}{2} \right)} + 1} + \frac{1}{\tan^{2}{\left(\frac{1}{2} \right)} + 1}$$
=
2
1 tan (1/2) 2*tan(1/2)
------------- + ------------- - -------------
2 2 2
1 + tan (1/2) 1 + tan (1/2) 1 + tan (1/2)
$$- \frac{2 \tan{\left(\frac{1}{2} \right)}}{\tan^{2}{\left(\frac{1}{2} \right)} + 1} + \frac{\tan^{2}{\left(\frac{1}{2} \right)}}{\tan^{2}{\left(\frac{1}{2} \right)} + 1} + \frac{1}{\tan^{2}{\left(\frac{1}{2} \right)} + 1}$$
1/(1 + tan(1/2)^2) + tan(1/2)^2/(1 + tan(1/2)^2) - 2*tan(1/2)/(1 + tan(1/2)^2)
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.