Sr Examen
Integral de /(cos^2(1-2x)) dx
Solución
Ha introducido
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0 / | | 2 | cos (1 - 2*x) dx | / 0
$$\int\limits_{0}^{0} \cos^{2}{\left(1 - 2 x \right)}\, dx$$
Integral(cos(1 - 2*x)^2, (x, 0, 0))
Respuesta (Indefinida)
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/ | 3 4 2 | 2 x tan(-1/2 + x) tan (-1/2 + x) x*tan (-1/2 + x) 2*x*tan (-1/2 + x) | cos (1 - 2*x) dx = C + --------------------------------------- + --------------------------------------- - --------------------------------------- + --------------------------------------- + --------------------------------------- | 4 2 4 2 4 2 4 2 4 2 / 2 + 2*tan (-1/2 + x) + 4*tan (-1/2 + x) 2 + 2*tan (-1/2 + x) + 4*tan (-1/2 + x) 2 + 2*tan (-1/2 + x) + 4*tan (-1/2 + x) 2 + 2*tan (-1/2 + x) + 4*tan (-1/2 + x) 2 + 2*tan (-1/2 + x) + 4*tan (-1/2 + x)
$$\int \cos^{2}{\left(1 - 2 x \right)}\, dx = C + \frac{x \tan^{4}{\left(x - \frac{1}{2} \right)}}{2 \tan^{4}{\left(x - \frac{1}{2} \right)} + 4 \tan^{2}{\left(x - \frac{1}{2} \right)} + 2} + \frac{2 x \tan^{2}{\left(x - \frac{1}{2} \right)}}{2 \tan^{4}{\left(x - \frac{1}{2} \right)} + 4 \tan^{2}{\left(x - \frac{1}{2} \right)} + 2} + \frac{x}{2 \tan^{4}{\left(x - \frac{1}{2} \right)} + 4 \tan^{2}{\left(x - \frac{1}{2} \right)} + 2} - \frac{\tan^{3}{\left(x - \frac{1}{2} \right)}}{2 \tan^{4}{\left(x - \frac{1}{2} \right)} + 4 \tan^{2}{\left(x - \frac{1}{2} \right)} + 2} + \frac{\tan{\left(x - \frac{1}{2} \right)}}{2 \tan^{4}{\left(x - \frac{1}{2} \right)} + 4 \tan^{2}{\left(x - \frac{1}{2} \right)} + 2}$$
Gráfica
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.