Integral de 1/(x*(1+ln^2(x))) dx
Solución
Respuesta (Indefinida)
[src]
/
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| 1 / 2 \
| --------------- dx = C + RootSum\4*z + 1, i -> i*log(2*i + log(x))/
| / 2 \
| x*\1 + log (x)/
|
/
$$\int \frac{1}{x \left(\log{\left(x \right)}^{2} + 1\right)}\, dx = C + \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i + \log{\left(x \right)} \right)} \right)\right)}$$
/ 2 \ / 2 \
- RootSum\4*z + 1, i -> i*log(2*i)/ + RootSum\4*z + 1, i -> i*log(1 + 2*i)/
$$- \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i \right)} \right)\right)} + \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i + 1 \right)} \right)\right)}$$
=
/ 2 \ / 2 \
- RootSum\4*z + 1, i -> i*log(2*i)/ + RootSum\4*z + 1, i -> i*log(1 + 2*i)/
$$- \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i \right)} \right)\right)} + \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i + 1 \right)} \right)\right)}$$
-RootSum(4*_z^2 + 1, Lambda(_i, _i*log(2*_i))) + RootSum(4*_z^2 + 1, Lambda(_i, _i*log(1 + 2*_i)))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.