Integral de 1/(x*(1+ln^2(x))) dx
Solución
Respuesta (Indefinida)
[src]
/
|
| 1 / 2 \
| --------------- dx = C + RootSum\4*z + 1, i -> i*log(2*i + log(x))/
| / 2 \
| x*\1 + log (x)/
|
/
∫x(log(x)2+1)1dx=C+RootSum(4z2+1,(i↦ilog(2i+log(x))))
Gráfica
/ 2 \ / 2 \
- RootSum\4*z + 1, i -> i*log(2*i)/ + RootSum\4*z + 1, i -> i*log(1 + 2*i)/
−RootSum(4z2+1,(i↦ilog(2i)))+RootSum(4z2+1,(i↦ilog(2i+1)))
=
/ 2 \ / 2 \
- RootSum\4*z + 1, i -> i*log(2*i)/ + RootSum\4*z + 1, i -> i*log(1 + 2*i)/
−RootSum(4z2+1,(i↦ilog(2i)))+RootSum(4z2+1,(i↦ilog(2i+1)))
-RootSum(4*_z^2 + 1, Lambda(_i, _i*log(2*_i))) + RootSum(4*_z^2 + 1, Lambda(_i, _i*log(1 + 2*_i)))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.