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Ecuación diferencial sqrt(y^2+1dx)=xydy

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
   ____________                  
  /       2                      
\/  dx + y (x)      d            
--------------- = x*--(y(x))*y(x)
       dx           dx           
$$\frac{\sqrt{dx + y^{2}{\left(x \right)}}}{dx} = x y{\left(x \right)} \frac{d}{d x} y{\left(x \right)}$$
sqrt(dx + y^2)/dx = x*y*y'
Respuesta [src]
              __________________________________
             /               2                  
            /    2        log (x)   2*C1*log(x) 
y(x) = -   /   C1  - dx + ------- + ----------- 
          /                   2          dx     
        \/                  dx                  
$$y{\left(x \right)} = - \sqrt{C_{1}^{2} + \frac{2 C_{1} \log{\left(x \right)}}{dx} - dx + \frac{\log{\left(x \right)}^{2}}{dx^{2}}}$$
             __________________________________
            /               2                  
           /    2        log (x)   2*C1*log(x) 
y(x) =    /   C1  - dx + ------- + ----------- 
         /                   2          dx     
       \/                  dx                  
$$y{\left(x \right)} = \sqrt{C_{1}^{2} + \frac{2 C_{1} \log{\left(x \right)}}{dx} - dx + \frac{\log{\left(x \right)}^{2}}{dx^{2}}}$$
Clasificación
factorable
separable
lie group
separable Integral