lny=ax+by la ecuación
El profesor se sorprenderá mucho al ver tu solución correcta😉
Solución
Resolución de la ecuación paramétrica
Se da la ecuación con parámetro:
log(y)=ax+byКоэффициент при x равен
−aentonces son posibles los casos para a :
a<0a=0Consideremos todos los casos con detalles:
Con
a<0la ecuación será
−by+x+log(y)=0su solución
x=by−log(y)Con
a=0la ecuación será
−by+log(y)=0su solución
Suma y producto de raíces
[src]
/(-im(b*y) + arg(y))*re(a) (-re(b*y) + log(|y|))*im(a)\ (-im(b*y) + arg(y))*im(a) (-re(b*y) + log(|y|))*re(a)
I*|------------------------- - ---------------------------| + ------------------------- + ---------------------------
| 2 2 2 2 | 2 2 2 2
\ im (a) + re (a) im (a) + re (a) / im (a) + re (a) im (a) + re (a)
i(−(re(a))2+(im(a))2(log(∣y∣)−re(by))im(a)+(re(a))2+(im(a))2(−im(by)+arg(y))re(a))+(re(a))2+(im(a))2(log(∣y∣)−re(by))re(a)+(re(a))2+(im(a))2(−im(by)+arg(y))im(a)
/(-im(b*y) + arg(y))*re(a) (-re(b*y) + log(|y|))*im(a)\ (-im(b*y) + arg(y))*im(a) (-re(b*y) + log(|y|))*re(a)
I*|------------------------- - ---------------------------| + ------------------------- + ---------------------------
| 2 2 2 2 | 2 2 2 2
\ im (a) + re (a) im (a) + re (a) / im (a) + re (a) im (a) + re (a)
i(−(re(a))2+(im(a))2(log(∣y∣)−re(by))im(a)+(re(a))2+(im(a))2(−im(by)+arg(y))re(a))+(re(a))2+(im(a))2(log(∣y∣)−re(by))re(a)+(re(a))2+(im(a))2(−im(by)+arg(y))im(a)
/(-im(b*y) + arg(y))*re(a) (-re(b*y) + log(|y|))*im(a)\ (-im(b*y) + arg(y))*im(a) (-re(b*y) + log(|y|))*re(a)
I*|------------------------- - ---------------------------| + ------------------------- + ---------------------------
| 2 2 2 2 | 2 2 2 2
\ im (a) + re (a) im (a) + re (a) / im (a) + re (a) im (a) + re (a)
i(−(re(a))2+(im(a))2(log(∣y∣)−re(by))im(a)+(re(a))2+(im(a))2(−im(by)+arg(y))re(a))+(re(a))2+(im(a))2(log(∣y∣)−re(by))re(a)+(re(a))2+(im(a))2(−im(by)+arg(y))im(a)
(-re(b*y) + log(|y|))*re(a) - I*((-arg(y) + im(b*y))*re(a) + (-re(b*y) + log(|y|))*im(a)) - (-arg(y) + im(b*y))*im(a)
---------------------------------------------------------------------------------------------------------------------
2 2
im (a) + re (a)
(re(a))2+(im(a))2−i((log(∣y∣)−re(by))im(a)+(im(by)−arg(y))re(a))+(log(∣y∣)−re(by))re(a)−(im(by)−arg(y))im(a)
((-re(b*y) + log(|y|))*re(a) - i*((-arg(y) + im(b*y))*re(a) + (-re(b*y) + log(|y|))*im(a)) - (-arg(y) + im(b*y))*im(a))/(im(a)^2 + re(a)^2)
/(-im(b*y) + arg(y))*re(a) (-re(b*y) + log(|y|))*im(a)\ (-im(b*y) + arg(y))*im(a) (-re(b*y) + log(|y|))*re(a)
x1 = I*|------------------------- - ---------------------------| + ------------------------- + ---------------------------
| 2 2 2 2 | 2 2 2 2
\ im (a) + re (a) im (a) + re (a) / im (a) + re (a) im (a) + re (a)
x1=i(−(re(a))2+(im(a))2(log(∣y∣)−re(by))im(a)+(re(a))2+(im(a))2(−im(by)+arg(y))re(a))+(re(a))2+(im(a))2(log(∣y∣)−re(by))re(a)+(re(a))2+(im(a))2(−im(by)+arg(y))im(a)
x1 = i*(-(log(|y|) - re(b*y))*im(a)/(re(a)^2 + im(a)^2) + (-im(b*y) + arg(y))*re(a)/(re(a)^2 + im(a)^2)) + (log(|y|) - re(b*y))*re(a)/(re(a)^2 + im(a)^2) + (-im(b*y) + arg(y))*im(a)/(re(a)^2 + im(a)^2)