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log(1/3)(x-1)>=x²-2x-9

log(1/3)(x-1)>=x²-2x-9 desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
                     2          
log(1/3)*(x - 1) >= x  - 2*x - 9
$$\left(x - 1\right) \log{\left(\frac{1}{3} \right)} \geq \left(x^{2} - 2 x\right) - 9$$
(x - 1)*log(1/3) >= x^2 - 2*x - 9
Solución de la desigualdad en el gráfico
Respuesta rápida [src]
   /        ______________                     ______________                   \
   |       /         2                        /         2                       |
   |     \/  40 + log (3)    -2 + log(3)    \/  40 + log (3)    -2 + log(3)     |
And|x <= ----------------- - -----------, - ----------------- - ----------- <= x|
   \             2                2                 2                2          /
$$x \leq - \frac{-2 + \log{\left(3 \right)}}{2} + \frac{\sqrt{\log{\left(3 \right)}^{2} + 40}}{2} \wedge - \frac{\sqrt{\log{\left(3 \right)}^{2} + 40}}{2} - \frac{-2 + \log{\left(3 \right)}}{2} \leq x$$
(x <= sqrt(40 + log(3)^2)/2 - (-2 + log(3))/2)∧(-sqrt(40 + log(3)^2)/2 - (-2 + log(3))/2 <= x)
Respuesta rápida 2 [src]
        ______________                  ______________          
       /         2                     /         2              
     \/  40 + log (3)    log(3)      \/  40 + log (3)    log(3) 
[1 - ----------------- - ------, 1 + ----------------- - ------]
             2             2                 2             2    
$$x\ in\ \left[- \frac{\sqrt{\log{\left(3 \right)}^{2} + 40}}{2} - \frac{\log{\left(3 \right)}}{2} + 1, - \frac{\log{\left(3 \right)}}{2} + 1 + \frac{\sqrt{\log{\left(3 \right)}^{2} + 40}}{2}\right]$$
x in Interval(-sqrt(log(3)^2 + 40)/2 - log(3)/2 + 1, -log(3)/2 + 1 + sqrt(log(3)^2 + 40)/2)
Gráfico
log(1/3)(x-1)>=x²-2x-9 desigualdades