log(3)*2*x < log(3)*(3 - 6*x)
(2*x)*log(3) < (3 - 6*x)*log(3)
And(-oo < x, x < 3/8)
(-oo < x)∧(x < 3/8)
(-oo, 3/8)
x in Interval.open(-oo, 3/8)