Sr Examen
Integral de (e^(x)dx)/(4+e^(2x)) dx
Solución
Ha introducido
[src]
1 / | | x | E | -------- dx | 2*x | 4 + E | / 0
$$\int\limits_{0}^{1} \frac{e^{x}}{e^{2 x} + 4}\, dx$$
Integral(E^x/(4 + E^(2*x)), (x, 0, 1))
Respuesta (Indefinida)
[src]
/ / x\ | |e | | x atan|--| | E \2 / | -------- dx = C + -------- | 2*x 2 | 4 + E | /
$$\int \frac{e^{x}}{e^{2 x} + 4}\, dx = C + \frac{\operatorname{atan}{\left(\frac{e^{x}}{2} \right)}}{2}$$
Gráfica
Respuesta
[src]
/ 2 \ / 2 \ - RootSum\16*z + 1, i -> i*log(1 + 8*i)/ + RootSum\16*z + 1, i -> i*log(E + 8*i)/
$$- \operatorname{RootSum} {\left(16 z^{2} + 1, \left( i \mapsto i \log{\left(8 i + 1 \right)} \right)\right)} + \operatorname{RootSum} {\left(16 z^{2} + 1, \left( i \mapsto i \log{\left(8 i + e \right)} \right)\right)}$$
=
=
/ 2 \ / 2 \ - RootSum\16*z + 1, i -> i*log(1 + 8*i)/ + RootSum\16*z + 1, i -> i*log(E + 8*i)/
$$- \operatorname{RootSum} {\left(16 z^{2} + 1, \left( i \mapsto i \log{\left(8 i + 1 \right)} \right)\right)} + \operatorname{RootSum} {\left(16 z^{2} + 1, \left( i \mapsto i \log{\left(8 i + e \right)} \right)\right)}$$
-RootSum(16*_z^2 + 1, Lambda(_i, _i*log(1 + 8*_i))) + RootSum(16*_z^2 + 1, Lambda(_i, _i*log(E + 8*_i)))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.