Sr Examen
Integral de sqrt(tg(x-1))/cos(x-1)^2 dx
Solución
Ha introducido
[src]
p
1 + -
4
/
|
| ____________
| \/ tan(x - 1)
| -------------- dx
| 2
| cos (x - 1)
|
/
___
\/ 3
$$\int\limits_{\sqrt{3}}^{\frac{p}{4} + 1} \frac{\sqrt{\tan{\left(x - 1 \right)}}}{\cos^{2}{\left(x - 1 \right)}}\, dx$$
Integral(sqrt(tan(x - 1))/cos(x - 1)^2, (x, sqrt(3), 1 + p/4))
Respuesta (Indefinida)
[src]
/ / | | | ____________ | ____________ | \/ tan(x - 1) | \/ tan(x - 1) | -------------- dx = C + | -------------- dx | 2 | 2 | cos (x - 1) | cos (x - 1) | | / /
$$\int \frac{\sqrt{\tan{\left(x - 1 \right)}}}{\cos^{2}{\left(x - 1 \right)}}\, dx = C + \int \frac{\sqrt{\tan{\left(x - 1 \right)}}}{\cos^{2}{\left(x - 1 \right)}}\, dx$$
Respuesta
[src]
p
1 + -
4
/
|
| _____________
| \/ tan(-1 + x)
| --------------- dx
| 2
| cos (-1 + x)
|
/
___
\/ 3
$$\int\limits_{\sqrt{3}}^{\frac{p}{4} + 1} \frac{\sqrt{\tan{\left(x - 1 \right)}}}{\cos^{2}{\left(x - 1 \right)}}\, dx$$
=
=
p
1 + -
4
/
|
| _____________
| \/ tan(-1 + x)
| --------------- dx
| 2
| cos (-1 + x)
|
/
___
\/ 3
$$\int\limits_{\sqrt{3}}^{\frac{p}{4} + 1} \frac{\sqrt{\tan{\left(x - 1 \right)}}}{\cos^{2}{\left(x - 1 \right)}}\, dx$$
Integral(sqrt(tan(-1 + x))/cos(-1 + x)^2, (x, sqrt(3), 1 + p/4))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.