Sr Examen
Ecuación diferencial (sin(2y)^2-2(siny)^2+2x)dy=sin(2)ydx
El profesor se sorprenderá mucho al ver tu solución correcta😉
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Solución
Ha introducido
[src]
2 d 2 d d
sin (2*y(x))*--(y(x)) - 2*sin (y(x))*--(y(x)) + 2*x*--(y(x)) = sin(2)*y(x)
dx dx dx
$$2 x \frac{d}{d x} y{\left(x \right)} - 2 \sin^{2}{\left(y{\left(x \right)} \right)} \frac{d}{d x} y{\left(x \right)} + \sin^{2}{\left(2 y{\left(x \right)} \right)} \frac{d}{d x} y{\left(x \right)} = y{\left(x \right)} \sin{\left(2 \right)}$$
2*x*y' - 2*sin(y)^2*y' + sin(2*y)^2*y' = y*sin(2)
Gráfico para el problema de Cauchy
Clasificación
factorable
1st exact
1st power series
lie group
1st exact Integral
Respuesta numérica
[src]
(x, y):
(-10.0, 0.75)
(-7.777777777777778, 0.6684512984244233)
(-5.555555555555555, 0.5721406790747253)
(-3.333333333333333, 0.45044681080941823)
(-1.1111111111111107, 0.26688862033933936)
(1.1111111111111107, 0.04532337661175048)
(3.333333333333334, 0.07462201884129449)
(5.555555555555557, 0.09409543275134541)
(7.777777777777779, 0.10962354023181411)
(10.0, 0.12287198381216186)
(10.0, 0.12287198381216186)