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log9(x-3)*logx-3(x+4)>=log^29(x+4) desigualdades

En la desigualdad la incógnita

Solución

Ha introducido [src]
log(x - 3)                          29       
----------*log(x) - 3*(x + 4) >= log  (x + 4)
  log(9)                                     
$$\frac{\log{\left(x - 3 \right)}}{\log{\left(9 \right)}} \log{\left(x \right)} - 3 \left(x + 4\right) \geq \log{\left(x + 4 \right)}^{29}$$
(log(x - 3)/log(9))*log(x) - 3*(x + 4) >= log(x + 4)^29