$$\lim_{x \to \infty}\left(\frac{\sinh{\left(\frac{1}{x} \right)}}{\log{\left(\log{\left(\frac{x}{x^{4} + 1} \right)} \right)}^{2}}\right) = 0$$
$$\lim_{x \to 0^-}\left(\frac{\sinh{\left(\frac{1}{x} \right)}}{\log{\left(\log{\left(\frac{x}{x^{4} + 1} \right)} \right)}^{2}}\right) = -\infty$$
Más detalles con x→0 a la izquierda$$\lim_{x \to 0^+}\left(\frac{\sinh{\left(\frac{1}{x} \right)}}{\log{\left(\log{\left(\frac{x}{x^{4} + 1} \right)} \right)}^{2}}\right) = \infty$$
Más detalles con x→0 a la derecha$$\lim_{x \to 1^-}\left(\frac{\sinh{\left(\frac{1}{x} \right)}}{\log{\left(\log{\left(\frac{x}{x^{4} + 1} \right)} \right)}^{2}}\right) = \frac{-1 + e^{2}}{- 2 e \pi^{2} + 2 e \log{\left(\log{\left(2 \right)} \right)}^{2} + 4 e i \pi \log{\left(\log{\left(2 \right)} \right)}}$$
Más detalles con x→1 a la izquierda$$\lim_{x \to 1^+}\left(\frac{\sinh{\left(\frac{1}{x} \right)}}{\log{\left(\log{\left(\frac{x}{x^{4} + 1} \right)} \right)}^{2}}\right) = \frac{-1 + e^{2}}{- 2 e \pi^{2} + 2 e \log{\left(\log{\left(2 \right)} \right)}^{2} + 4 e i \pi \log{\left(\log{\left(2 \right)} \right)}}$$
Más detalles con x→1 a la derecha$$\lim_{x \to -\infty}\left(\frac{\sinh{\left(\frac{1}{x} \right)}}{\log{\left(\log{\left(\frac{x}{x^{4} + 1} \right)} \right)}^{2}}\right) = 0$$
Más detalles con x→-oo