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Ecuación diferencial tan(y)+(y/(1+x^2))*dx+(arctan(x)+x*(sec(y))^2-2*sin(y))*dy=0

El profesor se sorprenderá mucho al ver tu solución correcta😉

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Para el problema de Cauchy:

y() =
y'() =
y''() =
y'''() =
y''''() =

Gráfico:

interior superior

Solución

Ha introducido [src]
tan(y(x))    y(x)    d                    d                         2       d           
--------- + ------ + --(y(x))*atan(x) - 2*--(y(x))*sin(y(x)) + x*sec (y(x))*--(y(x)) = 0
    dx           2   dx                   dx                                dx          
            1 + x                                                                       
$$x \sec^{2}{\left(y{\left(x \right)} \right)} \frac{d}{d x} y{\left(x \right)} - 2 \sin{\left(y{\left(x \right)} \right)} \frac{d}{d x} y{\left(x \right)} + \operatorname{atan}{\left(x \right)} \frac{d}{d x} y{\left(x \right)} + \frac{y{\left(x \right)}}{x^{2} + 1} + \frac{\tan{\left(y{\left(x \right)} \right)}}{dx} = 0$$
x*sec(y)^2*y' - 2*sin(y)*y' + atan(x)*y' + y/(x^2 + 1) + tan(y)/dx = 0
Clasificación
1st power series
lie group