Sr Examen
Integral de (sqrt(1+tgx))/(cos^2x) dx
Solución
Ha introducido
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-pi ---- 4 / | | ____________ | \/ 1 + tan(x) | -------------- dx | 2 | cos (x) | / 0
$$\int\limits_{0}^{- \frac{\pi}{4}} \frac{\sqrt{\tan{\left(x \right)} + 1}}{\cos^{2}{\left(x \right)}}\, dx$$
Integral(sqrt(1 + tan(x))/cos(x)^2, (x, 0, -pi/4))
Respuesta (Indefinida)
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/ / | | | ____________ | ____________ | \/ 1 + tan(x) | \/ 1 + tan(x) | -------------- dx = C + | -------------- dx | 2 | 2 | cos (x) | cos (x) | | / /
$$\int \frac{\sqrt{\tan{\left(x \right)} + 1}}{\cos^{2}{\left(x \right)}}\, dx = C + \int \frac{\sqrt{\tan{\left(x \right)} + 1}}{\cos^{2}{\left(x \right)}}\, dx$$
Respuesta
[src]
-pi ---- 4 / | | ____________ | \/ 1 + tan(x) | -------------- dx | 2 | cos (x) | / 0
$$\int\limits_{0}^{- \frac{\pi}{4}} \frac{\sqrt{\tan{\left(x \right)} + 1}}{\cos^{2}{\left(x \right)}}\, dx$$
=
=
-pi ---- 4 / | | ____________ | \/ 1 + tan(x) | -------------- dx | 2 | cos (x) | / 0
$$\int\limits_{0}^{- \frac{\pi}{4}} \frac{\sqrt{\tan{\left(x \right)} + 1}}{\cos^{2}{\left(x \right)}}\, dx$$
Integral(sqrt(1 + tan(x))/cos(x)^2, (x, 0, -pi/4))
Estos ejemplos se pueden aplicar para introducción de los límites de integración inferior y superior.