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Límite de la función cot(pi*x)*log(tan(x+pi/4))

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Ha introducido [src]
     /             /   /    pi\\\
 lim |cot(pi*x)*log|tan|x + --|||
x->0+\             \   \    4 ///
$$\lim_{x \to 0^+}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right)$$
Limit(cot(pi*x)*log(tan(x + pi/4)), x, 0)
Método de l'Hopital
Tenemos la indeterminación de tipo
0/0,

tal que el límite para el numerador es
$$\lim_{x \to 0^+} \log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} = 0$$
y el límite para el denominador es
$$\lim_{x \to 0^+} \frac{1}{\cot{\left(\pi x \right)}} = 0$$
Vamos a probar las derivadas del numerador y denominador hasta eliminar la indeterminación.
$$\lim_{x \to 0^+}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right)$$
=
Introducimos una pequeña modificación de la función bajo el signo del límite
$$\lim_{x \to 0^+}\left(\log{\left(\tan{\left(\frac{4 x + \pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)}}{\frac{d}{d x} \frac{1}{\cot{\left(\pi x \right)}}}\right)$$
=
$$\lim_{x \to 0^+}\left(- \frac{\left(\tan^{2}{\left(x + \frac{\pi}{4} \right)} + 1\right) \cot^{2}{\left(\pi x \right)}}{\pi \left(- \cot^{2}{\left(\pi x \right)} - 1\right) \tan{\left(x + \frac{\pi}{4} \right)}}\right)$$
=
$$\lim_{x \to 0^+}\left(- \frac{2 \cot^{2}{\left(\pi x \right)}}{\pi \left(- \cot^{2}{\left(\pi x \right)} - 1\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \frac{1}{- \cot^{2}{\left(\pi x \right)} - 1}}{\frac{d}{d x} \left(- \frac{\pi}{2 \cot^{2}{\left(\pi x \right)}}\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{2 \cot^{4}{\left(\pi x \right)}}{\pi \left(\cot^{4}{\left(\pi x \right)} + 2 \cot^{2}{\left(\pi x \right)} + 1\right)}\right)$$
=
$$\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \frac{1}{\cot^{4}{\left(\pi x \right)} + 2 \cot^{2}{\left(\pi x \right)} + 1}}{\frac{d}{d x} \frac{\pi}{2 \cot^{4}{\left(\pi x \right)}}}\right)$$
=
$$\lim_{x \to 0^+}\left(- \frac{\left(- 4 \pi \left(- \cot^{2}{\left(\pi x \right)} - 1\right) \cot^{3}{\left(\pi x \right)} - 4 \pi \left(- \cot^{2}{\left(\pi x \right)} - 1\right) \cot{\left(\pi x \right)}\right) \cot^{5}{\left(\pi x \right)}}{2 \pi^{2} \left(- \cot^{2}{\left(\pi x \right)} - 1\right) \left(\cot^{4}{\left(\pi x \right)} + 2 \cot^{2}{\left(\pi x \right)} + 1\right)^{2}}\right)$$
=
$$\lim_{x \to 0^+}\left(- \frac{\left(- 4 \pi \left(- \cot^{2}{\left(\pi x \right)} - 1\right) \cot^{3}{\left(\pi x \right)} - 4 \pi \left(- \cot^{2}{\left(\pi x \right)} - 1\right) \cot{\left(\pi x \right)}\right) \cot^{5}{\left(\pi x \right)}}{2 \pi^{2} \left(- \cot^{2}{\left(\pi x \right)} - 1\right) \left(\cot^{4}{\left(\pi x \right)} + 2 \cot^{2}{\left(\pi x \right)} + 1\right)^{2}}\right)$$
=
$$\frac{2}{\pi}$$
Como puedes ver, hemos aplicado el método de l'Hopital (utilizando la derivada del numerador y denominador) 3 vez (veces)
Otros límites con x→0, -oo, +oo, 1
$$\lim_{x \to 0^-}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right) = \frac{2}{\pi}$$
Más detalles con x→0 a la izquierda
$$\lim_{x \to 0^+}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right) = \frac{2}{\pi}$$
$$\lim_{x \to \infty}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right)$$
Más detalles con x→oo
$$\lim_{x \to 1^-}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right) = - \infty \operatorname{sign}{\left(\log{\left(\tan{\left(\frac{\pi}{4} + 1 \right)} \right)} \right)}$$
Más detalles con x→1 a la izquierda
$$\lim_{x \to 1^+}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right) = \infty \operatorname{sign}{\left(\log{\left(\tan{\left(\frac{\pi}{4} + 1 \right)} \right)} \right)}$$
Más detalles con x→1 a la derecha
$$\lim_{x \to -\infty}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right)$$
Más detalles con x→-oo
Respuesta rápida [src]
2 
--
pi
$$\frac{2}{\pi}$$
A la izquierda y a la derecha [src]
     /             /   /    pi\\\
 lim |cot(pi*x)*log|tan|x + --|||
x->0+\             \   \    4 ///
$$\lim_{x \to 0^+}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right)$$
2 
--
pi
$$\frac{2}{\pi}$$
= 0.636619772367581
     /             /   /    pi\\\
 lim |cot(pi*x)*log|tan|x + --|||
x->0-\             \   \    4 ///
$$\lim_{x \to 0^-}\left(\log{\left(\tan{\left(x + \frac{\pi}{4} \right)} \right)} \cot{\left(\pi x \right)}\right)$$
2 
--
pi
$$\frac{2}{\pi}$$
= 0.636619772367581
= 0.636619772367581
Respuesta numérica [src]
0.636619772367581
0.636619772367581